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x^2+86x+168=0
a = 1; b = 86; c = +168;
Δ = b2-4ac
Δ = 862-4·1·168
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-82}{2*1}=\frac{-168}{2} =-84 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+82}{2*1}=\frac{-4}{2} =-2 $
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